## вторник, 24 декабря 2013 г.

### Codility. Train. Perm-Check ★

A non-empty zero-indexed array A consisting of N integers is given.
permutation is a sequence containing each element from 1 to N once, and only once.
For example, array A such that:
```    A = 4
A = 1
A = 3
A = 2```
is a permutation, but array A such that:
```    A = 4
A = 1
A = 3```
is not a permutation.
The goal is to check whether array A is a permutation.
Write a function:
def solution(A)
that, given a zero-indexed array A, returns 1 if array A is a permutation and 0 if it is not.
For example, given array A such that:
```    A = 4
A = 1
A = 3
A = 2```
the function should return 1.
Given array A such that:
```    A = 4
A = 1
A = 3```
the function should return 0.
Assume that:
• N is an integer within the range [1..100,000];
• each element of array A is an integer within the range [1..1,000,000,000].
Complexity:
• expected worst-case time complexity is O(N);
• expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.

Solution:
```def solution(A):
A.sort(reverse=True)
return 1 if A == len(A) and len(set(A)) == len(A) else 0
```

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